Newton

Algorithm

字数统计: 31阅读时长: 1 min

 2019/07/08   Share

https://leetcode.com/problems/sqrtx/discuss/25057/3-4-short-lines-Integer-Newton-Every-Language/24092

long r = x;
while (r*r > x)
    r = (r + x/r) / 2;
return r;

answer

原文作者：ReZero

原文链接：https://rezeros.github.io/2019/07/08/sqrt(x)/

发表日期：July 8th 2019, 5:27:58 pm

更新日期：March 10th 2020, 1:29:52 pm

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